Warning: implode(): Invalid arguments passed in /www/wwwroot/jobquiz.info/mdiscuss.php on line 336 What will be the output of the program? #include<stdio.h> int get(); int main() { const int x = get(); printf("%d", x); return 0; } int get() { return 20; } ?->(Show Answer!)
1. What will be the output of the program? #include<stdio.h> int get(); int main() { const int x = get(); printf("%d", x); return 0; } int get() { return 20; }
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By: guest on 01 Jun 2017 06.00 pm
Step 1: int get(); This is the function prototype for the funtion get(), it tells the compiler returns an integer value and accept no parameters. Step 2: const int x = get(); The constant variable x is declared as an integer data type and initialized with the value "20". The function get() returns the value "20". Step 3: printf("%d", x); It prints the value of the variable x. Hence the output of the program is "20".