Question Set

1. What will be the output of the program? #include<stdio.h> int main() { int i=0; for(; i<=5; i++); printf("%d", i); return 0; }





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: guest on 01 Jun 2017 06.01 pm
    Step 1: int i = 0; here variable i is an integer type and initialized to '0'.
    Step 2: for(; i<=5; i++); variable i=0 is already assigned in previous step. The semi-colon at the end of this for loop tells, "there is no more statement is inside the loop".

    Loop 1: here i=0, the condition in for(; 0<=5; i++) loop satisfies and then i is incremented by '1'(one)
    Loop 2: here i=1, the condition in for(; 1<=5; i++) loop satisfies and then i is incremented by '1'(one)
    Loop 3: here i=2, the condition in for(; 2<=5; i++) loop satisfies and then i is incremented by '1'(one)
    Loop 4: here i=3, the condition in for(; 3<=5; i++) loop satisfies and then i is increemented by '1'(one)
    Loop 5: here i=4, the condition in for(; 4<=5; i++) loop satisfies and then i is incremented by '1'(one)
    Loop 6: here i=5, the condition in for(; 5<=5; i++) loop satisfies and then i is incremented by '1'(one)
    Loop 7: here i=6, the condition in for(; 6<=5; i++) loop fails and then i is not incremented.
    Step 3: printf("%d", i); here the value of i is 6. Hence the output is '6'.
Show Similar Question And Answers
QA->Name the translatory program which translates the high level language into machine language before running the program?....
QA->An unauthorized program which functions from inside what seems to be an authorized program, thereby concealing what it is actually doing:....
QA->An unauthorized program which functions from inside what seems to be an authorized program, thereby concealing what it is actually doing:....
QA->An unauthorized program which functions from inside what seems to be an authorized program, thereby concealing what it is actually doing:....
QA->An unauthorized program which functions from inside what seems to be an authorized program, thereby concealing what it is actually doing:....
MCQ->What will be the output of the program? #include<stdio.h> int i; int fun1(int); int fun2(int); int main() { extern int j; int i=3; fun1(i); printf("%d,", i); fun2(i); printf("%d", i); return 0; } int fun1(int j) { printf("%d,", ++j); return 0; } int fun2(int i) { printf("%d,", ++i); return 0; } int j=1;....
MCQ->What will be the output of the program? #include<stdio.h> #include<stdarg.h> void fun1(char, int, int , float , char ); void fun2(char ch, ...); void (p1)(char, int, int , float , char ); void (p2)(char ch, ...); int main() { char ch='A'; int i=10; float f=3.14; char p="Hello"; p1=fun1; p2=fun2; (p1)(ch, i, &i, &f, p); (p2)(ch, i, &i, &f, p); return 0; } void fun1(char ch, int i, int pi, float pf, char p) { printf("%c %d %d %f %s \n", ch, i, pi, pf, p); } void fun2(char ch, ...) { int i, pi; float pf; char p; va_list list; printf("%c ", ch); va_start(list, ch); i = va_arg(list, int); printf("%d ", i); pi = va_arg(list, int); printf("%d ", pi); pf = va_arg(list, float); printf("%f ", pf); p = va_arg(list, char ); printf("%s", p); }....
MCQ->What will be the output of the program? #include<stdio.h> int fun(int, int); typedef int (pf) (int, int); int proc(pf, int, int); int main() { printf("%d\n", proc(fun, 6, 6)); return 0; } int fun(int a, int b) { return (a==b); } int proc(pf p, int a, int b) { return ((p)(a, b)); }....
MCQ->Which of the following statement is correct about the program given below? #include<iostream.h> int BixTest(int x, int y); int BixTest(int x, int y, int z = 5); int main() { cout<< BixTest(2, 4) << endl; return 0; } int BixTest(int x, int y) { return x y; } int BixTest(int x, int y, int z = 5) { return x y z; }....
MCQ->What will be the output of the program? #include int fun(int ptr); int main() { int i=10; const int ptr = &i; fun(&ptr); return 0; } int fun(int ptr) { int j = 223; int temp = &j; printf("Before changing ptr = %5x\n", ptr); const ptr = temp; printf("After changing ptr = %5x\n", ptr); return 0; }....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution