What will be the output of the program? #include<stdio.h> int main() { int a=0, b=1, c=3; ((a) ? &b : &a) = a ? b : c; printf("%d, %d, %d\n", a, b, c); return 0; } ?->(Show Answer!)

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What will be the output of the program? #include<stdio.h> int main() { int a=0, b=1, c=3; ((a) ? &b : &a) = a ? b : c; printf("%d, %d, %d\n", a, b, c); return 0; } ?->(Show Answer!)

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1. What will be the output of the program? #include<stdio.h> int main() { int a=0, b=1, c=3; ((a) ? &b : &a) = a ? b : c; printf("%d, %d, %d\n", a, b, c); return 0; }

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By: guest on 01 Jun 2017 06.01 pm

Step 1: int a=0, b=1, c=3; here variable a, b, and c are declared as integer type and initialized to 0, 1, 3 respectively. Step 2: *((a) ? &b : &a) = a ? b : c; The right side of the expression(a?b:c) becomes (0?1:3). Hence it return the value '3'. The left side of the expression *((a) ? &b : &a) becomes *((0) ? &b : &a). Hence this contains the address of the variable a *(&a). Step 3: *((a) ? &b : &a) = a ? b : c; Finally this statement becomes *(&a)=3. Hence the variable a has the value '3'. Step 4: printf("%d, %d, %d\n", a, b, c); It prints "3, 1, 3".

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