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What will be the output of the program? #include<stdio.h> #include<math.h> int main() { float n=1.54; printf("%f, %f\n", ceil(n), floor(n)); return 0; } ?->(Show Answer!)
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1. What will be the output of the program? #include<stdio.h> #include<math.h> int main() { float n=1.54; printf("%f, %f\n", ceil(n), floor(n)); return 0; }





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  • By: guest on 01 Jun 2017 06.01 pm
    ceil(x) round up the given value. It finds the smallest integer not < x.
    floor(x) round down the given value. It finds the smallest integer not > x.
    printf("%f, %f\n", ceil(n), floor(n)); In this line ceil(1.54) round up the 1.54 to 2 and floor(1.54) round down the 1.54 to 1. In the printf("%f, %f\n", ceil(n), floor(n)); statement, the format specifier "%f %f" tells output to be float value. Hence it prints 2.000000 and 1.000000.
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