What will be the output of the program? #include<stdio.h> #include<stdlib.h> int main() { int i=0; i++; if(i<=5) { printf("IndiaBIX"); exit(1); main(); } return 0; } ?->(Show Answer!)

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1. What will be the output of the program? #include<stdio.h> #include<stdlib.h> int main() { int i=0; i++; if(i<=5) { printf("IndiaBIX"); exit(1); main(); } return 0; }

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By: guest on 01 Jun 2017 06.01 pm

Step 1: int i=0; The variable i is declared as in integer type and initialized to '0'(zero). Step 2: i++; Here variable i is increemented by 1. Hence i becomes '1'(one). Step 3: if(i<=5) becomes if(1 <=5). Hence the if condition is satisfied and it enter into if block statements. Step 4: printf("IndiaBIX"); It prints "IndiaBIX". Step 5: exit(1); This exit statement terminates the program execution. Hence the output is "IndiaBIx".

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