Question Set

1. If the shear force along a section of a beam is zero, the bending moment at the section is






Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->What minimum number of non-zero non-collinear vectors is required to produce a zero vector?....
QA->The minimum number of non-zero non-collinear vectors required to produce a zero vector is?....
QA->The average of 20 numbers is zero. Of them , at the most ,how many may be greater than zero?....
QA->The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?....
QA->The average of 20 numbers is zero. Of them, How many of them may be greater than zero, at the most?....
MCQ->If the shear force at a section of beam under bending is equal to zero then the bending moment at the section is....
MCQ->If the shear force along a section of a beam is zero, the bending moment at the section is....
MCQ->Consider the following statements : In the beam shown in the given figure, for all positions of load W (except x = 0) 1. bending moment is maximum at B 2. bending moment is maximum under load 3. deflection is zero at A 4. deflection is zero at B Of these statements : ....
MCQ->Consider the following statements : 1. Point of contraflexure is the point where the bending moment is maximum. 2. Point of cantraflexure is the point where the bending moment changes sign. 3. Point of contraflexure is the point where the shear force is zero. Which of these statements is/are correct ?....
MCQ->A force of 500 N acts at the top of the two-member frame. If the members are in smooth contact with one another at A, B, and C with no fasteners, determine the shear force developed at a horizontal section through point D of the support. Also, what are the axial force, shear force and moment at point E?....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution