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1 - 1 + 1 - 2 + 1 - 3 + ... up to n terms = ? n n n ?->(Show Answer!)
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1. 1 - 1 + 1 - 2 + 1 - 3 + ... up to n terms = ? n n n





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  • By: guest on 01 Jun 2017 05.46 pm
    Given sum = (1 + 1 + 1 + ... to n terms) - 1 + 2 + 3 + ... to n terms n n n = n - n 1 + 1     [ Ref: nth terms = (n/n) = 1] 2 n = n - n + 1 2 = 1 (n - 1) 2
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