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1. Find the value of ix if each resistance is of 3 Ω and each battery is of 6 V.





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  • By: guest on 02 Jun 2017 12.54 am
    Using Mesh analysis Loop 1 : 6 = 9i1 - 3i4 ...(i) Loop 2: 6 + 6 = - 6i2 i2 = - 2A ...(ii) Loop 3: 6 = 9i3 - 3i4 ...(iii) Loop 4: 6 = 9i4 - 3i3 - 3i1 ...(iv) Solving the above equations simultaneously i1 = i3 = 1.1428 A i4 = 1.432 A ∴ ix = i4 - i3 = 0.2892 A.
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