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1. In the circuit shown in the figure, steady-state was reached when the switch S was open. The switch was closed at t = 0. The initial value of the current through the capacitor 2 C is





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  • By: guest on 02 Jun 2017 01.06 am
    At steady state capacitor will be open and inductor will short circuited. V across 2C will be = 12v .
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