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1. In the circuit shown, the steady state is reached with S open S is closed at t = 0, the current I in the 1 Ω resistor connected is to be determined at t = 0+ is given by





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  • By: guest on 02 Jun 2017 01.07 am
    If steady is reached L will be short circuited the current in 1 Ω resistor I = 4/2 2A. It will act as current source in parallel with inductor. Now apply superposition theorem consider 4 volt source, current source will be open and inductor also open. Current in R' = 1 Ω resistor = 2A. When current source consider, voltage source will be short circuited and current due to inductor is 1A in opposite direction. Total current 2 - 1 = 1 A.
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