1. What is the name of the method used to start a thread execution?





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: guest on 02 Jun 2017 01.26 am
    Option B is Correct. The start() method causes this thread to begin execution; the Java Virtual Machine calls the run method of this thread. Option A is wrong. There is no init() method in the Thread class. Option C is wrong. The run() method of a thread is like the main() method to an application. Starting the thread causes the object's run method to be called in that separately executing thread. Option D is wrong. The resume() method is deprecated. It resumes a suspended thread.
Show Similar Question And Answers
QA->Which chemical is used by weavers for moisturing thread?....
QA->The execution of the Pallivasal Hydroelectric Scheme was during the period of?....
QA->Hang by a thread....
QA->Numerous thread like structures which forms the skeleton of the nucleus; is known as?....
QA->Which oil is used in the floatation method for the purification of ores?....
MCQ->Which two can be used to create a new Thread? Extend java.lang.Thread and override the run() method. Extend java.lang.Runnable and override the start() method. Implement java.lang.Thread and implement the run() method. Implement java.lang.Runnable and implement the run() method. Implement java.lang.Thread and implement the start() method.....
MCQ->Which two are valid constructors for Thread? Thread(Runnable r, String name) Thread() Thread(int priority) Thread(Runnable r, ThreadGroup g) Thread(Runnable r, int priority)....
MCQ->What will be the output of the program? class s1 implements Runnable { int x = 0, y = 0; int addX() {x++; return x;} int addY() {y++; return y;} public void run() { for(int i = 0; i < 10; i++) System.out.println(addX() + " " + addY()); } public static void main(String args[]) { s1 run1 = new s1(); s1 run2 = new s1(); Thread t1 = new Thread(run1); Thread t2 = new Thread(run2); t1.start(); t2.start(); } }....
MCQ->What will be the output of the program? class s implements Runnable { int x, y; public void run() { for(int i = 0; i < 1000; i++) synchronized(this) { x = 12; y = 12; } System.out.print(x + " " + y + " "); } public static void main(String args[]) { s run = new s(); Thread t1 = new Thread(run); Thread t2 = new Thread(run); t1.start(); t2.start(); } }....
MCQ->What will be the output of the program? public class Test { public static void main (String [] args) { final Foo f = new Foo(); Thread t = new Thread(new Runnable() { public void run() { f.doStuff(); } }); Thread g = new Thread() { public void run() { f.doStuff(); } }; t.start(); g.start(); } } class Foo { int x = 5; public void doStuff() { if (x < 10) { // nothing to do try { wait(); } catch(InterruptedException ex) { } } else { System.out.println("x is " + x++); if (x >= 10) { notify(); } } } }....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution