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What will be the output of the program? #include<stdio.h> #include<string.h> int main() { char dest[] = {97, 97, 0}; char src[] = "aaa"; int i; if((i = memcmp(dest, src, 2))==0) printf("Got it"); else printf("Missed"); return 0; } ?->(Show Answer!)
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1. What will be the output of the program? #include<stdio.h> #include<string.h> int main() { char dest[] = {97, 97, 0}; char src[] = "aaa"; int i; if((i = memcmp(dest, src, 2))==0) printf("Got it"); else printf("Missed"); return 0; }





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  • By: guest on 01 Jun 2017 06.02 pm
    memcmp compares the first 2 bytes of the blocks dest and src as unsigned chars. So, the ASCII value of 97 is 'a'.
    if((i = memcmp(dest, src, 2))==0) When comparing the array dest and src as unsigned chars, the first 2 bytes are same in both variables.so memcmp returns '0'.
    Then, the if(0=0) condition is satisfied. Hence the output is "Got it".
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