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What will be the output of the program if the size of pointer is 4-bytes? #include<stdio.h> int main() { printf("%d, %d\n", sizeof(NULL), sizeof("")); return 0; } ?->(Show Answer!)
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1. What will be the output of the program if the size of pointer is 4-bytes? #include<stdio.h> int main() { printf("%d, %d\n", sizeof(NULL), sizeof("")); return 0; }





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  • By: guest on 01 Jun 2017 06.02 pm
    In TurboC, the output will be 2, 1 because the size of the pointer is 2 bytes in 16-bit platform.

    But in Linux, the output will be 4, 1 because the size of the pointer is 4 bytes.

    This difference is due to the platform dependency of C compiler.
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