1. Except for monoatomic gases, the molal heat capacity at constant volume for all gases is __________ Kcal/Kg mole.° K.





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->For a body moving with constant speed in a horizontal circle; what remains constant?....
QA->For a body moving with constant speed in a horizontal circle, what remains constant?....
QA->At constant pressure the volume of a definite mass of a gas is directly proportional to the?....
QA->Volume of a sphere is c.c. What is the volume of a sphere having half its radius?....
QA->വിശിഷ്ടതാപധാരിത [ Specific Heat capacity ] ഏറ്റവും കൂടുതലുള്ള മൂലകം?....
MCQ->Except for monoatomic gases, the molal heat capacity at constant volume for all gases is __________ Kcal/Kg mole.° K.....
MCQ->One mole of methane undergoes complete combustion in a stoichiometric amount of air. The reaction proceeds as CH4 + 2O2 → CO2 + 2H2O. Both the reactants and products are in gas phase. ΔH°298 = - 730 kJ/mole of methane. If the average specific heat of all the gases/vapour is 40 J/mole.K, the maximum temperature rise of the exhaust gases in °C would be approximately equal to....
MCQ->A rigid vessel containing three moles of nitrogen gas at 30°C is heated to 250°C. Assume the average capacities of nitrogen to be Cp = 29.1 J/mole.°C and, Cv = 20.8 J/mole.°C. The heat required, neglecting the heat capacity of the vessel, is....
MCQ->A batch adiabatic reactor at an initial temperature of 373°K is being used for the reaction, A B. Assume the heat of reaction is - 1kJ/mole at 373°K and heat capacity of both A and B to be constant and equal to 50J/mole.K. The temperature rise after a conversion of 0.5 will be....
MCQ->The value of Cp & Cv respectively for monoatomic gases in Kcal/kg Mole . °K are....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution