Question Set

1. If the long chord and tangent length of a circular curve of radius R are equal the angle of deflection, is






Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->Find the maximum velocity for the overturn of a car moving on a circular track of radius 100 m. The co-efficient of friction between the road and tyre is 0.2?....
QA->The ratio between the radius and height of a circular one of volume 314 cm (cube) is 5:Its height is....
QA->A train having a length of 240 metre passes a post in 24 seconds. How long will it take to pass a platform having a length of 650 metre?....
QA->How long does a train 110 metres long running at a speed of 36 km/hour take to cross a bridge of 132 metres in length?....
QA->A train 110ms long passes a telegraph pole in 3 seconds. How long will it take to cross railway platform 165 ms long....
MCQ->If the long chord and tangent length of a circular curve of radius R are equal the angle of deflection, is....
MCQ->If L is the length of the transition curves provided on either side of a circular curve of radius R, the maximum angle of deflection with tangent for the junctions of the transition curve and circular curve, is....
MCQ->A road is provided with a horizontal circular curve having deflection angle of 55° and centre line radius of 250 m. A transition curve is to be provided at each end of the circular curve of such a length that the rate of gain of radial acceleration is 0.3 m/s3 at a speed of 50 km per hour. Length of the transition curve required at each of the ends is....
MCQ->The ratio of the length of long chord and the tangent length of a circular curve of radius R deflecting through angle Δ, is....
MCQ->If S is the length of a subchord and R is the radius of simple curve, the angle of deflection between its tangent and sub-chord, in minutes, is equal to....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution