Question Set

1. Calculate the ripple of a capacitor filter for a peak rectified voltage of 40 V, a capacitor value C = 75 F, and a load current of 40 mA.





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

Show Similar Question And Answers
QA->The device used for converting current from a lower voltage to a higher voltage is known as?....
QA->A man who can swim 48 m/minute in still water. He swims 200 m against the current and 200 m with the current. If the difference between those two times is 10 minutes, what is the speed of the current?....
QA->A man who can swim 48 m/minute in still water. He swims 200 m against the current and 200 m with the current. If the difference between those two times is 10 minutes, what is the speed of the current?....
QA->Speed of a swimmer when moving in the direction perpendicular to the direction of the current is 16 km/h, speed of the current is 3 km/h. So the speed of the swimmer against the current will be (in km/h):....
QA->Speed of a speed-boat when moving in the direction perpendicular to the direction of the current is 25 km/h, speed of the current is 5 km/h. So, the speed of the boat against the current will be:....
MCQ->Calculate the ripple of a capacitor filter for a peak rectified voltage of 40 V, a capacitor value C = 75 F, and a load current of 40 mA.....
MCQ->If a peak rectified voltage for the full-wave filter circuit is 40 V, calculate the filter dc voltage if C = 75 F and load current is 40 mA.....
MCQ->A ________ -wave rectified signal has less ripple than a ________ -wave rectified signal and is thus better to apply to a filter.....
MCQ->A bridge rectifier circuit has a dc load current of 10 mA and a filter capacitance of 1000 μF. The peak to peak ripple voltage is....
MCQ->Assertion (A): A rectifier with inductor filter is more efficient for high load current.Reason (R): In rectifier with inductor filter we can use a larger choke to reduce ripple, larger choke will have higher dc resistance which will result in lower dc output voltage for higher load current.

....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution