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1. The Boolean expression for the circuit of the given figure





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  • By: guest on 01 Jun 2017 11.52 pm
    B and C in parallel give B + C. Similarly D and E in parallel give D + E. (B + C) in series with (D + E) give (B + C) (D + E). Since F is in parallel we get F + (B + C) (D + E). Finally A is in series. Therefore we get A[F + (B + C) (D + E)].
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