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1. In the following limiter circuit, an input voltage V1 = 10 sin 100p t applied. Assume that the diode drop is 0.7 V when it is forward biased. The zener breakdown voltage is 6.8 V The maximum and minimum values of the output voltage respectively are





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  • By: guest on 02 Jun 2017 12.54 am
    During +ve part of Vi D1 will be forward biased Zener diode is reverse biased Thus net voltage = 6.8 + 0.7 = 4.5 V During -ve part of Vi D2 will be forward biased D1 will be reversed biased Thus net voltage = -0.7 V .
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