1. A parallel plate capacitor has its length, width and separation doubled. It fringing effects are neglected, to keep the capacitance same, the dielectric constant must be





Ask Your Doubts Here

Type in
(Press Ctrl+g to toggle between English and the chosen language)

Comments

  • By: guest on 02 Jun 2017 12.59 am
    . When dimensions are changed, A become four times and d becomes twice. Since ∈0 is constant, ∈r must be halved to keep C constant.
Show Similar Question And Answers
QA->The length of a rectangular floor is 2 meters more than its width and its perimeter is 20 meters, then its area is....
QA->The length of a park is 50m and the breadth is 35m. The width of a path running around the park is 5m. Find the area of the path?....
QA->A, B and C start at the same time in the same direction to run around a circular stadium. A completes a round in 252 seconds, B in 308 seconds and c in 198 seconds, all starting at the same point. After what time will they again at the starting point ?....
QA->Which is the planet its length of its day and the tilt of its axis are almost identical to those of the earth?....
QA->Two satellite are moving in the same circular orbit around the earth they must have the same?....
MCQ->A parallel plate capacitor has its length, width and separation doubled. It fringing effects are neglected, to keep the capacitance same, the dielectric constant must be....
MCQ->Assertion (A): In a parallel plate capacitor having area of plate 1 m2 and plate separation 1 m, the capacitance C and resistance R are given by C = ∈0∈'r and R = where ω is frequency, ∈r' and ∈r" are real and imaginary parts of dielectric constant.Reason (R): The imaginary part of electric constant is responsible for dielectric losses.

....
MCQ->A parallel plate capacitor with air as dielectric has a capacitance C. If the dielectric has a dielectric constant ∈r and the remaining dimensions are the same, the capacitance will be....
MCQ->A parallel plate capacitor has area of plate A and plate separation d. Its capacitance is C. A metallic plate P of area A and negligible thickness is added as shown in Figure. The new value of capacitance is ....
MCQ->Assertion (A): ∈r can be determined experimentally by measuring the capacitance of a parallel plate capacitor with and without the dielectric.Reason (R): Capacitance of a parallel plate capacitor = .

....
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use | Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions
Question ANSWER With Solution