1. What will be the output of the program? public class Test { public int aMethod() { static int i = 0; i++; return i; } public static void main(String args[]) { Test test = new Test(); test.aMethod(); int j = test.aMethod(); System.out.println(j); } }





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  • By: guest on 02 Jun 2017 01.25 am
    Compilation failed because static was an illegal start of expression - method variables do not have a modifier (they are always considered local).
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