54101. In figure v1 = 8 V and v2 = 4 V. Which diode will conduct?
54102. The load impedance ZL of a CE amplifier has R and L in series. The phase difference between output and input will be
54103. This is the first time that I ......... her song.?
54104. If an amplifier with gain of - 1000 and feedback factor β = - 0.1 had a gain change of 20% due to temperature, the change in gain of the feedback amplifier would be
54105. In figure The minimum and maximum load currents are
54106. In figure, VEB = 0.6 V, β = 99. Then VC and IC are
54107. The input impedance of op-amp circuit of figure is
54108. In a BJT circuit a pnp transistor is replaced by npn transistor. To analyse the new circuit
54109. To protect the diodes in a rectifier and capacitor input filter circuit it is necessary to use
54110. The output V0 in figure is
54111. In a CE amplifier the input impedance is equal to the ratio of
54112. For a system to work, as oscillator the total phase shift of the loop gain must be equal to
54113. An amplifier has a large ac input signal. The clipping occurs on both the peaks. The output voltage will be nearly a
54114. The transistor of following figure in Si diode with a base current of 40 μA and ICBO = 0, if VBB = 6V, RE = 2 kΩ and β = 90, IBQ = 20 μA then RB =
54115. In the amplifier circuit of figure hfe = 100 and hie = 1000 Ω. The voltage gain of amplifier is about
54116. The efficiency of a full wave rectifier using centre tapped transformer is twice that in full wave bridge rectifier.
54117. Assertion (A): CE amplifier is the most widely used BJT amplifierReason (R): CE amplifier has zero phase difference between input and output
54118. Assertion (A): For large signal variations an amplifier circuit has to be analysed graphicallyReason (R): The output characteristics of a transistor is nonlinear.
54119. Negative feedback reduces noise originating at the amplifier input.
54120. Maximum efficiency of class B power amplifier is 50%.
54121. In figure what is the base current if VBE = 0.7 V
54122. In figure ID = 4 mA. Then VS =
54123. The self bias provides
54124. In figure what is value of IC if βdc = 100. Neglect VBE
54125. Who was the Prime minister of India when the 73rd and 74th amendments of constitution were passed.?
54126. Consider the following statements : A clamper circuit adds or subtracts a dc voltage to a waveformdoes not change the waveformamplifiers the waveform Which are correct?
54127. In figure v1 = 8 V and v2 = 8 V. Which diode will conduct?
54128. A forward voltage of 9 V is applied to a diode in series with a 1 kΩ load resistor. The voltage across load resistor is zero. It indicates that
54129. Which power amplifier can deliver maximum load power?
54130. A CB amplifier has re = 6 Ω, RL = 600 Ω and a = 0.98. The voltage gain is
54131. A bridge rectifier circuit has input of 50 Hz frequency. The load resistance is RL and filter capacitance is C. For good output wave shape, the time constant RLC should be at least equal to
54132. Si transistor of following figure has a = 0.9 and ICE= 0, VEE = 5 V and VCC = 13 V, then RE will be if IEQ = 1 mA
54133. In class C operation of an amplifier circuit, the collector current exists for
54134. The 'h' parameters of the circuit shown in the figure are hib = 25 Ω, hfb = 0.999 and hob = 10-6Ω The Voltage gain is
54135. An exponential amplifier has diode in feedback path.
54136. DC amplifiers have a tendency to be unstable.
54137. A half wave diode rectifier has a capacitance input filter. If input voltage is Vm sin ωt, PIV is
54138. An amplifier with loop gain Aβ will be more stable for value of Aβ as
54139. Study the circuit of figure and examine the following statements
It is an active low pass finer.It is a second order filter.The change in gain is 40 dB/decade. Which of the above statements are correct?
54140. In a circuit of figure, Vs = 10 cos(ωt) power drawn by the 2Ω resistor is 4 watts. The power factor is
54141. The quiescent collector current IC, and collector to emitter voltage VCE in a CE connection are the values when
54142. In the op-amp circuit of figure, V0 =
54143. Figure shows the self bias circuit for CE amplifier and its equivalent circuit. VBB and RB respectively are
54144. Figure is a 24 Vr stabilized power supply. The zener is 24 V, 600 mW. The minimum zener current is 10 mA. Proper values R and maximum load current are
54145. The open loop gain of an amplifier is 200. If negative feedback with β = 0.2 is used, the closed loop gain will be
54146. In a class C power amplifier the input signal has a frequency of 250 kHz. If the collector current pulses are 0.1 μs wide, the duty cycle of current waveform is
54147. In figure as the load resistance is changed
54148. In figure, voltage across R2 = + 10 V. If VBE = 0.7 V and VE = 0.7 V and RE = 10 kΩ, current through RE is
54149. A 12 kHz pulse wave-form is amplified by a circuit having an Upper cut-off frequency of 1 MHz. The minimum input pulse width that can be accurately reproduced is
54150. Feedback factor may be less or more than 1.