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You Are On Multi Choice Question Bank SET 1082

54101. In figure v1 = 8 V and v2 = 4 V. Which diode will conduct?





54102. The load impedance ZL of a CE amplifier has R and L in series. The phase difference between output and input will be





54103. This is the first time that I ......... her song.?





54104. If an amplifier with gain of - 1000 and feedback factor β = - 0.1 had a gain change of 20% due to temperature, the change in gain of the feedback amplifier would be





54105. In figure The minimum and maximum load currents are





54106. In figure, VEB = 0.6 V, β = 99. Then VC and IC are





54107. The input impedance of op-amp circuit of figure is





54108. In a BJT circuit a pnp transistor is replaced by npn transistor. To analyse the new circuit





54109. To protect the diodes in a rectifier and capacitor input filter circuit it is necessary to use





54110. The output V0 in figure is





54111. In a CE amplifier the input impedance is equal to the ratio of





54112. For a system to work, as oscillator the total phase shift of the loop gain must be equal to





54113. An amplifier has a large ac input signal. The clipping occurs on both the peaks. The output voltage will be nearly a





54114. The transistor of following figure in Si diode with a base current of 40 μA and ICBO = 0, if VBB = 6V, RE = 2 kΩ and β = 90, IBQ = 20 μA then RB =





54115. In the amplifier circuit of figure hfe = 100 and hie = 1000 Ω. The voltage gain of amplifier is about





54116. The efficiency of a full wave rectifier using centre tapped transformer is twice that in full wave bridge rectifier.



54117. Assertion (A): CE amplifier is the most widely used BJT amplifierReason (R): CE amplifier has zero phase difference between input and output





54118. Assertion (A): For large signal variations an amplifier circuit has to be analysed graphicallyReason (R): The output characteristics of a transistor is nonlinear.





54119. Negative feedback reduces noise originating at the amplifier input.



54120. Maximum efficiency of class B power amplifier is 50%.



54121. In figure what is the base current if VBE = 0.7 V





54122. In figure ID = 4 mA. Then VS =





54123. The self bias provides





54124. In figure what is value of IC if βdc = 100. Neglect VBE





54125. Who was the Prime minister of India when the 73rd and 74th amendments of constitution were passed.?





54126. Consider the following statements : A clamper circuit adds or subtracts a dc voltage to a waveformdoes not change the waveformamplifiers the waveform Which are correct?





54127. In figure v1 = 8 V and v2 = 8 V. Which diode will conduct?





54128. A forward voltage of 9 V is applied to a diode in series with a 1 kΩ load resistor. The voltage across load resistor is zero. It indicates that





54129. Which power amplifier can deliver maximum load power?





54130. A CB amplifier has re = 6 Ω, RL = 600 Ω and a = 0.98. The voltage gain is





54131. A bridge rectifier circuit has input of 50 Hz frequency. The load resistance is RL and filter capacitance is C. For good output wave shape, the time constant RLC should be at least equal to





54132. Si transistor of following figure has a = 0.9 and ICE= 0, VEE = 5 V and VCC = 13 V, then RE will be if IEQ = 1 mA





54133. In class C operation of an amplifier circuit, the collector current exists for





54134. The 'h' parameters of the circuit shown in the figure are hib = 25 Ω, hfb = 0.999 and hob = 10-6Ω The Voltage gain is





54135. An exponential amplifier has diode in feedback path.



54136. DC amplifiers have a tendency to be unstable.



54137. A half wave diode rectifier has a capacitance input filter. If input voltage is Vm sin ωt, PIV is





54138. An amplifier with loop gain Aβ will be more stable for value of Aβ as





54139. Study the circuit of figure and examine the following statements It is an active low pass finer.It is a second order filter.The change in gain is 40 dB/decade. Which of the above statements are correct?





54140. In a circuit of figure, Vs = 10 cos(ωt) power drawn by the 2Ω resistor is 4 watts. The power factor is





54141. The quiescent collector current IC, and collector to emitter voltage VCE in a CE connection are the values when





54142. In the op-amp circuit of figure, V0 =





54143. Figure shows the self bias circuit for CE amplifier and its equivalent circuit. VBB and RB respectively are





54144. Figure is a 24 Vr stabilized power supply. The zener is 24 V, 600 mW. The minimum zener current is 10 mA. Proper values R and maximum load current are





54145. The open loop gain of an amplifier is 200. If negative feedback with β = 0.2 is used, the closed loop gain will be





54146. In a class C power amplifier the input signal has a frequency of 250 kHz. If the collector current pulses are 0.1 μs wide, the duty cycle of current waveform is





54147. In figure as the load resistance is changed





54148. In figure, voltage across R2 = + 10 V. If VBE = 0.7 V and VE = 0.7 V and RE = 10 kΩ, current through RE is





54149. A 12 kHz pulse wave-form is amplified by a circuit having an Upper cut-off frequency of 1 MHz. The minimum input pulse width that can be accurately reproduced is





54150. Feedback factor may be less or more than 1.



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