<<= Back Next =>>
You Are On Multi Choice Question Bank SET 1086

54301. A virtual ground is a ground for

54302. As compared to a full wave diode rectifier circuit using centre tapped transformer, the bridge diode rectifier circuit has the main advantage of

54303. A dc power supply has no load voltage of 30 V and full load voltage of 25 V at full load current of 1 A. The output resistance and voltage regulation respectively are

54304. The main advantage of CC amplifier is

54305. If a = 0.995, IE = 10 mA, ICO = 0.5 mA, then ICEO will be

54306. Assertion (A): In class C amplifier the efficiency is more than that for other classes of amplifiersReason (R): In class C amplifier we can get high efficiency over a wideband

54307. In the following figure C = 0.02 μF, and Vth is known to be of frequency ω = 107 rad/sec and rd = 2.5 Ω and ZTh = RTh = 10 Ω Then phase angle between id and Vd

54308. A class C amplifier has input frequency of 200 kHz. If width of collector pulses is 0.1 μs, duty cycle is

54309. Output of a phase splitter is

54310. In a transistor the minimum and maximum values of βdc are 100 and 121. The proper value of βdc to be used to locate Q point is

54311. The input to an op-amp integrating amplifier is a constant voltage. The output will be

54312. FET amplifier is more difficult to analyse than BJT amplifier.

54313. To bypass a 100 ohm emitter resistor at

54314. In a CE amplifier the dc load line is the same as ac load line when

54315. If the output current wave shape of class C circuit has a period of 1 μs and a pulse width of 0.006 μs, the duty cycle is

54316. Which configuration is suitable for impedance matching?

54317. A BJT is said to be operating in saturation region if

54318. If an amplifier with gain of - 100 and feedback of β = - 0.1 has a gain change of 20% due to temperature the change in gain of the feedback amplifier will be

54319. In figure the cut in voltage of diode is 0.7 V and its bulk resistance is 20 Ω. The peak value of circuit current of during positive and negative half cycles are

54320. A voltage gain of a CE amplifier connected in collector to base configuration is 50. Collector to base resistor RF = 1 kΩ, RC = 4Ω, the O/P resistance R0 =?

54321. A voltage multiplier circuit, using diodes and capacitors is suitable for

54322. In a CE amplifier the ac emitter resistance

54323. Heat sink results in

54324. Who was the first to perform the surgery of human heart transplant?

54325. In a CE amplifier, the output voltage is equal to product of

54326. In figure, VG =

54327. A diode can have a very high forward resistance.

54328. In figure the voltage drop across diode is 0.7 V. Then the voltage across diode during negative half cycle is

54329. In figure vi = 10 mV dc maximum. The maximum possible dc output offset voltage is

54330. A transistor with a = 0.9 and ICBO = 10 μA is biased so that IBQ = 90 μA. Then ICQ will be

54331. The current through R1 is(If β = 99, VBE = 0.74 V)

54332. Which of the following can be used as a buffer amplifier?

54333. The feedback technique employed in the following circuit is

54334. A second order active bandpass filter can be obtained by cascading LP second order filter having higher cut off frequency fOH with a second order HP filter having lower cut off frequency fOL provided

54335. In figure the approximate voltages of

54336. The open loop gain of an amplifier is 50 but likely to decrease by 20% due to various factors. If negative feedback with β = 0.1 is used, the change in gain will be about

54337. An increase in ambient temperature means that maximum power rating of transistor

54338. Two CE stages are coupled through a capacitor. To calculate the quiescent base current of the two transistors, the capacitor is treated as

54339. If it is desired to have low output impedance in an amplifier circuit then we should use

54340. Generally the gain of a transistor amplifier falls at high frequencies due to the

54341. Which one of the following is connect expression of id for figure?

54342. A voltage tripler circuit and voltage quadrupler circuit use identical components. Then

54343. A Ge diode operated at a junction temperature of 27°C. For a forward current of 10 mA, VD is found to be 0.3 V. If VD = 0.4 V then forward current will be

54344. In a power amplifier the collector current flows for 270° of the input cycle. The operations is

54345. An amplifier has input impedance of 4 kΩ and output impedance of 80 kΩ. It is used in negative feedback circuit with 10% feedback. If open loop gain is 90, the closed loop input and output impedances are

54346. In figure the current through resistor R

54347. In a negative feedback amplifier A = 100, β = 0.04 and Vs = 50 mV, then feedback will be

54348. For an npn transistor connected as shown in the figure VBE = 0.7 volts. Given that reverse saturation current of the junction at room temperature 300K is 10-13A, the emitter current.

<<= Back Next =>>
Terms And Service:We do not guarantee the accuracy of available data ..We Provide Information On Public Data.. Please consult an expert before using this data for commercial or personal use
DMCA.com Protection Status Powered By:Omega Web Solutions
© 2002-2017 Omega Education PVT LTD...Privacy | Terms And Conditions