54302. As compared to a full wave diode rectifier circuit using centre tapped transformer, the bridge diode rectifier circuit has the main advantage of
54303. A dc power supply has no load voltage of 30 V and full load voltage of 25 V at full load current of 1 A. The output resistance and voltage regulation respectively are
54304. The main advantage of CC amplifier is
54305. If a = 0.995, IE = 10 mA, ICO = 0.5 mA, then ICEO will be
54306. Assertion (A): In class C amplifier the efficiency is more than that for other classes of amplifiersReason (R): In class C amplifier we can get high efficiency over a wideband
54307. In the following figure C = 0.02 μF, and Vth is known to be of frequency ω = 107 rad/sec and rd = 2.5 Ω and ZTh = RTh = 10 Ω Then phase angle between id and Vd
54308. A class C amplifier has input frequency of 200 kHz. If width of collector pulses is 0.1 μs, duty cycle is
54309. Output of a phase splitter is
54310. In a transistor the minimum and maximum values of βdc are 100 and 121. The proper value of βdc to be used to locate Q point is
54311. The input to an op-amp integrating amplifier is a constant voltage. The output will be
54312. FET amplifier is more difficult to analyse than BJT amplifier.
54313. To bypass a 100 ohm emitter resistor at
54314. In a CE amplifier the dc load line is the same as ac load line when
54315. If the output current wave shape of class C circuit has a period of 1 μs and a pulse width of 0.006 μs, the duty cycle is
54316. Which configuration is suitable for impedance matching?
54317. A BJT is said to be operating in saturation region if
54318. If an amplifier with gain of - 100 and feedback of β = - 0.1 has a gain change of 20% due to temperature the change in gain of the feedback amplifier will be
54319. In figure the cut in voltage of diode is 0.7 V and its bulk resistance is 20 Ω. The peak value of circuit current of during positive and negative half cycles are
54320. A voltage gain of a CE amplifier connected in collector to base configuration is 50. Collector to base resistor RF = 1 kΩ, RC = 4Ω, the O/P resistance R0 =?
54321. A voltage multiplier circuit, using diodes and capacitors is suitable for
54322. In a CE amplifier the ac emitter resistance
54323. Heat sink results in
54324. Who was the first to perform the surgery of human heart transplant?
54325. In a CE amplifier, the output voltage is equal to product of
54326. In figure, VG =
54327. A diode can have a very high forward resistance.
54328. In figure the voltage drop across diode is 0.7 V. Then the voltage across diode during negative half cycle is
54329. In figure vi = 10 mV dc maximum. The maximum possible dc output offset voltage is
54330. A transistor with a = 0.9 and ICBO = 10 μA is biased so that IBQ = 90 μA. Then ICQ will be
54331. The current through R1 is(If β = 99, VBE = 0.74 V)
54332. Which of the following can be used as a buffer amplifier?
54333. The feedback technique employed in the following circuit is
54334. A second order active bandpass filter can be obtained by cascading LP second order filter having higher cut off frequency fOH with a second order HP filter having lower cut off frequency fOL provided
54335. In figure the approximate voltages of
54336. The open loop gain of an amplifier is 50 but likely to decrease by 20% due to various factors. If negative feedback with β = 0.1 is used, the change in gain will be about
54337. An increase in ambient temperature means that maximum power rating of transistor
54338. Two CE stages are coupled through a capacitor. To calculate the quiescent base current of the two transistors, the capacitor is treated as
54339. If it is desired to have low output impedance in an amplifier circuit then we should use
54340. Generally the gain of a transistor amplifier falls at high frequencies due to the
54341. Which one of the following is connect expression of id for figure?
54342. A voltage tripler circuit and voltage quadrupler circuit use identical components. Then
54343. A Ge diode operated at a junction temperature of 27°C. For a forward current of 10 mA, VD is found to be 0.3 V. If VD = 0.4 V then forward current will be
54344. In a power amplifier the collector current flows for 270° of the input cycle. The operations is
54345. An amplifier has input impedance of 4 kΩ and output impedance of 80 kΩ. It is used in negative feedback circuit with 10% feedback. If open loop gain is 90, the closed loop input and output impedances are
54346. In figure the current through resistor R
54347. In a negative feedback amplifier A = 100, β = 0.04 and Vs = 50 mV, then feedback will be
54348. For an npn transistor connected as shown in the figure VBE = 0.7 volts. Given that reverse saturation current of the junction at room temperature 300K is 10-13A, the emitter current.