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1. An FM transmitter delivers 80W to a load of 30 W when no modulation is present. The carrier is now frequency modulated by a single sinusoidal signal and the peak frequency deviation is so adjusted to make the amplitude of the second sideband is zero in the given output. J0(0, 0) = 1, J0(2, 4) = 0, J0(3.8) = - 0.4, J0(5.1)= - 0.1 J1(2, 4) = 0.52, J1((3.8) = 0, J1(5.1) = - 0.33, J2(2.4) = 0.1 J2(3.8)= 0.41, J2(5.1) = 0 The power in all the remaining sidebands is :





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  • By: guest on 02 Jun 2017 12.55 am
    Total power of the FM transmitter = 80 W to a load of 50 W second side band amplitude = J2(β) = 0 ∴ β = 5.1 Average Power = (J0(β))2 x 100 = (0.16)2 x 100 = 2.56 W Power in all remaining = 80 - 2.56 = 77.44 .
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