56951. In the expression A + BC, the total number of minterms will be
56952. Use privileges in windows are stored in
56953. Which of the following is non-saturating?
56954. The number of digits in octal system is
56955. The access time of a word in 4 MB main memory is 100 ms. The access time of a word in a 32 kb data cache memory is 10 ns. The average data cache bit ratio is 0.95. The efficiency of memory access time is
56956. The expression Y = p M (0, 1, 3, 4) is
56957. An 8 bit DAC has a full scale output of 2 mA and full scale error of ± 0.5%. If input is 10000000 the range of outputs is
56958. Decimal 43 in hexadecimal and BCD number system is respectively.
56959. The circuit of the given figure realizes the function
56960. An AND gate has two inputs A and B and one inhibit input 3, Output is 1 if
56961. The greatest negative number which can be stored is 8 bit computer using 2's complement arithmetic is
56962. A JK flip flop has tpd= 12 ns. The largest modulus of a ripple counter using these flip flops and operating at 10 MHz is
56963. The basic storage element in a digital system is
56964. In a ripple counter,
56965. A 12 bit ADC is used to convert analog voltage of 0 to 10 V into digital. The resolution is
56966. For the truth table of the given figure Y =
56967. A full adder can be made out of
56968. If the functions w, x, y, z are as follows.
w = R + P Q + R S ,
x = PQR S + PQR S + PQ R S
Then
56969. The output of a half adder is
56970. Minimum number of 2-input NAND gates required to implement the function F = (x + y ) (Z + W) is
56971. Which device has one input and many outputs?
56972. A carry look ahead adder is frequently used for addition because
56973. The counter in the given figure is
56974. In register index addressing mode the effective address is given by
56975. 7BF16 = __________ 2
56976. For the minterm designation Y = ∑ m (1, 3, 5, 7) the complete expression is
56977. Zero suppression is not used in actual practice.
56978. A counter type A/D converter contains a 4 bit binary ladder and a counter driven by a 2 MHz clock. Then conversion time
56979. The hexadecimal number (3E8)16 is equal to decimal number
56980. The number of distinct Boolean expression of 4 variables is
56981. The fixed count that should be used so that the output register will represent the input for a 6 bit dual slope A/D converter uses a reference of -6v and a 1 MHz clock. It uses a fixed count of 40 (101000).
56982. For the K map in the given figure the simplified Boolean expression is
56983. A memory system of size 16 k bytes is to be designed using memory chips which have 12 address lines and 4 data lines each. The number of such chips required to design the memory system is
56984. In a 7 segment display, LEDs b and c lit up. The decimal number displayed is
56985. AB + AB =
56986. In a BCD to 7 segment decoder the minimum and maximum number of outputs active at any time is
56987. A three state switch has three outputs. These are
56988. Maxterm designation for A + B + C is
56989. 1's complement of 11100110 is
56990. Assertion (A): A demultiplexer can be used as a decoder.Reason (R): A demultiplexer can be built by using AND gates only.
56991. Assertion (A): The output of a NOR gate is equal to the complement of OR of input variables. Reason (R): A XOR gate is a universal gate.
56992. The number of bits in ASCII is
56993. 4 bit 2's complement representation of a decimal number is 1000. The number is
56994. In a D latch
56995. A 4 : 1 multiplexer requires __________ data select line.
56996. The number of unused states in a 4 bit Johnson counter is
56997. It is desired to display the digit 7 using a seven segment display. The LEDs to be turned on are
56998. For a MOD-12 counter, the FF has a tpd = 60 ns The NAND gate has a tpd of 25 n sec. The clock frequency is